因为字数限制，进行分割。 二、课后练习答案：（不抄题目，没有课本的人可以到网上去下一本） 2.1. #include<iostream> using namespace std; void main() {     int a=42486;     cout<<"42486的8进制输出："<<oct<<a         <<",42486的16进制输出："<<hex<<a<<dec<<endl;//效果是持续的     unsigned b=42486;     cout<<signed int(b)<<endl;//result:42486,在我的机器上还没有超出范围 //本题原考虑在16位机器上实验，目前多为32位机器，故不会超过范围的 } 2.2. #include<iostream> #include<iomanip> using namespace std; void main() {     const double PI=3.1415926;//不提倡使用宏定义也就是#define来定义     double circle,radius;     cin>>radius;     circle=2*PI*radius;     cout<<"圆周率为："<<setw(13)<<PI<<",The radius is:"<<setw(13)<<radius         <<",The circle is:"<<setw(13)<<circle<<endl; } 2.3.（我对输出格式比较厌烦，自己没有做，现在转引别人的答案） #include <iostream.h> #include <iomanip.h> const double e = 2.718281828; void main() {   cout <<setprecision(10) <<e <<endl        <<setiosflags(ios::fixed) <<setprecision(8) <<e <<endl        <<setiosflags(ios::scientific) <<e <<endl; } 2.4. #include<iostream> using namespace std; void main() {     const int numofstudent=500;     cout<<"\"How many students here?\"\n"<<"\""<<numofstudent<<"\""<<endl; } 2.5.（类似题目在《The C＋＋ programming language》答案序列一已经做得很多，我自己就不作了，答案转载别人的) #include <iostream.h> void main() {   cout <<"size of char           " <<sizeof(char) <<" byte\n"        <<"size of unsigned char  " <<sizeof(unsigned char) <<" byte\n"        <<"size of signed char    " <<sizeof(signed char) <<" byte\n"        <<"size of int            " <<sizeof(int) <<" byte\n"        <<"size of unsigned       " <<sizeof(unsigned) <<" byte\n"        <<"size of signed         " <<sizeof(signed) <<" byte\n"        <<"size of short          " <<sizeof(short) <<" byte\n"        <<"size of unsigned short " <<sizeof(unsigned short) <<" byte\n"        <<"size of long           " <<sizeof(long) <<" byte\n"        <<"size of signed long    " <<sizeof(signed long) <<" byte\n"        <<"size of unsigned long  " <<sizeof(unsigned long) <<" byte\n"        <<"size of float          " <<sizeof(float) <<" byte\n"        <<"size of double         " <<sizeof(double) <<" byte\n"        <<"size of long double    " <<sizeof(long double) <<" byte\n"; }

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