正文

简单模拟发扑克牌(c代码)2006-03-19 22:33:00

【评论】 【打印】 【字体: 】 本文链接:http://blog.pfan.cn/vfdff/11182.html

分享到:

/*仅输出一位玩家的牌*/#include<stdio.h>#include<conio.h>#include<math.h>#include<stdlib.h>int puke[52]={0};void input(int x,int y);void xipai(void){    int i=0,j=0,flag=0;    int x=0,y=0,z=0;    randomize();    for(i=0;i<52;i++)    {        do{            flag=0;            x=(int)(rand()%4)+1;            y=(int)(rand()%13)+1;            z=x*100+y;            for(j=0;j<i;j++)            {                if(puke[j]==z)                {                    flag=1;                    break;                }            }            if(flag==0)            {                puke[i]=z;            }        }while(flag);    }}void fapai(void){    int arr[13]={0};    int i=0,j=0,k=0;    int t=0,temp=0;    int a=0,b=0;    for(i=0;i<52;i++)    {        if(i%4==0)        {            arr[j]=puke[i];            j++;        }    }    for(j=1;j<12;j++)    {        t=13-j;        for(k=0;k<t;k++)        {            if(arr[k]>arr[k+1])            {                temp=arr[k];                arr[k]=arr[k+1];                arr[k+1]=temp;            }        }    }    for(k=0;k<13;k++)    {        a=arr[k]/100;        b=(((arr[k]/10)%10)*10)+arr[k]%10;        input(a,b);    }}void input(int x,int y){    switch(x)    {        case 1:            printf("H");            break;        case 2:            printf("D");            break;        case 3:            printf("C");            break;        case 4:            printf("S");            break;    }    switch(y)    {        case 1:            printf("2 ");            break;        case 2:            printf("3 ");            break;        case 3:            printf("4 ");            break;        case 4:            printf("5 ");            break;        case 5:            printf("6 ");            break;        case 6:            printf("7 ");            break;        case 7:            printf("8 ");            break;        case 8:            printf("9 ");            break;        case 9:            printf("10 ");            break;        case 10:            printf("J ");            break;        case 11:            printf("Q ");            break;        case 12:            printf("K ");            break;        case 13:            printf("A ");    }}int main(void){    int i;    clrscr();    xipai();    printf("\n\n\n\t");    fapai();    getch();    return 0;}   http://www.programfan.com/blog/article.asp?id=50  

阅读(3373) | 评论(1)


版权声明:编程爱好者网站为此博客服务提供商,如本文牵涉到版权问题,编程爱好者网站不承担相关责任,如有版权问题请直接与本文作者联系解决。谢谢!

评论

loading...
您需要登录后才能评论,请 登录 或者 注册