7. After a is initialized, which of the following expressions CANNOT access the face component of a correctly? struct card{ char *face; char *suit; } a, *aPtr = &a; (A) a.face (B) aPtr->face (C) (*aPtr).face (D) &a->face My answer: C Correct answer: D Select all to see the answers and the tips Tips: just consider *aPtr as a, they are totally equivalent. Similarily, a[i] is the same as *(a+i). so a[i][j] is the same as *(a+i)[j] See T10 10. For int a[3][4], (*p)[4]=a; Which of the following CANNOT access a[i][j] correctly? (A) *a[i]+j (B) (*(p+i))[j] (C) p[i][j] (D) *(*p+4*i+j) answer:A

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