7.
After a is initialized, which of the following expressions CANNOT access the face component of a correctly?

struct card{
    char *face;
    char *suit;
} a, *aPtr = &a;
(A) a.face             
(B) aPtr->face
(C) (*aPtr).face   
(D) &a->face

My answer: C

Correct answer: D

Select all to see the answers and the tips

Tips: just consider *aPtr as a, they are totally equivalent. Similarily, a[i] is the same as *(a+i). so a[i][j] is the same as *(a+i)[j]

See T10

10. For int a[3][4], (*p)[4]=a; Which of the following CANNOT access a[i][j]
correctly?

(A) *a[i]+j         
(B) (*(p+i))[j]
(C) p[i][j]          
(D) *(*p+4*i+j)

answer:A

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