博文

02(2005-08-22 18:33:00)

摘要:#include <iostream.h> #include <string.h> int main() {     int n,i;     char s[100];     while(cin>>n)     {         if(n==0) return 0;         int max=0;         for(i=0;i<n;i++)         {             gets(s);             if(s[strlen(s)-4]=='u')             {                 int sum=0;                 int pos=9;               ......

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jnu(The Circumference of the Circle)(2005-08-22 14:19:00)

摘要:#include <iostream.h> #define pi 3.141592653589793 #include <math.h> #include <fstream.h> ifstream f("circle.in"); #define cin f #include<iomanip.h> int main() {     //float a,b,c,d,e,f;     float x1,x2,x3,y1,y2,y3,x,y,r;     while(cin>>x1>>y1>>x2>>y2>>x3>>y3)     {         float k1,k2;         /*x1=(long)(a*10);         y1=(long)(b*10);         x2=(long)(c*10);         y2=(long)(d*10);         x3=(long)(e*10);         y3=(long)(f*10);         */               ......

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jnu(lotto)(2005-08-22 13:16:00)

摘要:#include <iostream.h> #include <fstream.h> ifstream f("lotto.in"); #define cin f int main() {     int i,j,k,l,m,n;     int a[12],b,num;     int flag=0;     while(cin>>num)     {         if(num==0) return 0;         if (flag==1) cout<<endl;         for(i=0;i<num;i++)         cin>>a[i];         for(i=0;i<=num-6;i++)         for(j=i+1;j<=num-5;j++)         for(k=j+1;k<=num-4;k++)         for(l=k+1;l<=num-3;l++)         for(m=l+1;m<=num-2;m++)       &n......

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另类排序(2005-08-22 10:19:00)

摘要:void sort(int a[],int n) {int i,j,t;   for(i=0;i<n-1;i++)     for(j=i+1;j<n;j++)       if(a[i]<a[j])   {t=a[i];a[i]=a[j];a[j]=t;} } main()   {int aa[10]={1,2,3,4,5,6,7,8,9,10},i;    sort(&aa[3],5);    for(i=0;i<10;i++)  printf("%d,",aa[i]);    printf("\n");    } 程序运行后的输出结果是 1,2,3,8,7,6,5,4,9,10, sort(&aa[3],5); 是从aa[3]开始起对数组的5个元素从大到小排序. 这样排序排序我也是第一次碰到. ......

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jnu(Parencodings)(2005-08-21 16:20:00)

摘要:#include <iostream.h> int main() {     int i,t,n,j,k;     int a[40],b[20];     int c[40];     cin>>t;     for(k=0;k<t;k++)     {         int pre;         int pos=0;         cin>>n;         for(j=0;j<n;j++)         cin>>b[j];         pre=0;         for(j=0;j<n;j++)         {             for(i=0;i<b[j]-pre;i++)             {             a[pos]=......

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jnu(Round and Round We Go)2(2005-08-21 15:36:00)

摘要:#include <iostream.h> #include <string.h> #include <fstream.h> ifstream f("c.in"); #define cin f int main() {     char a[61],b[61];     char c[61][61];     while(cin>>a)     {         int pos;         int i,j,k;         int iw;         int flag=0;         for(pos=0;pos<strlen(a);pos++)         {             for(i=0;i<strlen(a)-pos;i++)             c[pos][i]=a[i+pos];             for(i=strlen(a)-pos;i<strlen(a);i++)       &n......

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jnu(Round and Round We Go) || stu(1018)(2005-08-21 17:37:00)

摘要:#include <iostream.h> #include <string.h> #include <fstream.h> ifstream f("c.in"); #define cin f int main() {     char a[61],b[61];     char c[61][61];     while(cin>>a)     {         int pos;         int i,j,k;         int iw=0;         int flag=0;         for(pos=0;pos<strlen(a);pos++)         {             for(i=0;i<strlen(a)-pos;i++)             c[pos][i]=a[i+pos];             for(i=strlen(a)-pos;i<strlen(a);i++)       ......

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jnu(Primary Arithmetic)(2005-08-21 15:29:00)

摘要:#include <iostream.h> #include <string.h> #include <fstream.h> ifstream f("h.in"); #define cin f int main() {     char a[12],b[12],c[12];     while(cin>>a>>b)     {         if(strcmp(a,"0")==0 && strcmp(b,"0")==0)         return 0;         int flag=0;         int sum=0;         int i;         for(i=0;i<11;i++)         c[i]='0';         c[11]='\0';         for(i=strlen(a)-1;i>=0;i--)         c[strlen(a)-1-i]=a[i];         s......

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jnu(Easier Done Than Said?)(2005-08-21 15:28:00)

摘要:#include <iostream.h> #include <string.h> #include <fstream.h> ifstream f("e.in"); #define cin f int fun(char a) {     if(a=='a' || a=='e' || a=='i')     return 1;     else if(a=='o' || a=='u')     return 1;     return 0; }     int main() {     char a[100];     int i,j;     while(cin>>a)     {         int flag=0,flag2=0;         int sum1=0,sum2=0;         if(strcmp("end",a)==0) return 0;         if(strlen(a)==1)  goto loop;         for(i=0;i<strlen(a);i++)         if(fun(a[i]))    &n......

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pku(2262)(2005-08-20 13:24:00)

摘要:#include <iostream.h> #include <math.h> int fun(int n) {     int i;     for(i=2;i<=sqrt(n);i++)     if (n%i==0) return 0;     return 1; }     int main() {     int a;     while(cin>>a)     {         if(a==0) return 0;         int flag=0;         int b=3;         while(1)         {             if(fun(b) && fun(a-b))             {                            &nbs......

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