http://post.baidu.com/f?kz=66887754

//第一题
#include <stdio.h>

int m_day(int year,int month)/*此函数是给定年,月,计算此月有多少天.*/
{
if ((year%4==0 &&year%100!=0) || (year%400==0))
switch(month)
{
case 1: case 3: case 5: case 7: case 8: case 10: case 12: return 31;
case 4: case 6: case 9: case 11: return 30;
case 2: return 29;
}

else 
switch(month)
{
case 1: case 3: case 5: case 7: case 8: case 10: case 12: return 31;
case 4: case 6: case 9: case 11: return 30;
case 2: return 28;
}
}

int main()
{
 int y,m,d;
 while(scanf("%d-%d-%d",&y,&m,&d))
 {
  m+=2;
  if(m>12)
  {
   m-=12;
   y+=1;
  }
  if(d>m_day(y,m))
   d=m_day(y,m);
  printf("%d-",y);
  if(m<10)
   printf("0");
  printf("%d-",m);
  if(d<10)
   printf("0");
  printf("%d\n",d);
 }
}

//第2题
#include <iostream.h>
#include <math.h>
int main()
{
 int y;
 long n,s;
 float sum;
 while(cin>>y)
 {
  s=(long)pow(2,(y-1946)/10);
  n=1;
  sum=0;
  while(sum<s*log(2))
  {
   n++;
   sum+=log(n);
  }
  cout<<n-1<<endl;
  
 }
}

评论