#include <iostream.h> #include <string.h>   int s[24]={     1234,1243,1324,1342,1432,1423,     2134,2143,2314,2341,2431,2413,     3214,3241,3124,3142,3412,3421,     4231,4213,4321,4312,4132,4123};   int comp(int a,int b,int c,int d) {     char s[5];     cout<<a<<" "<<b<<" "<<c<<" "<<d<<endl;     cin>>s;     return s[0]-‘0’+s[2]-‘0’; }   int comp2(int a,int b,int c,int d) {     char s[5];     cout<<a<<" "<<b<<" "<<c<<" "<<d<<endl;     cin>>s;     if(s[0]!=4)//顺序还没有完全对     return 0;     else     return 1; }         int main() {     int i,j;     int guess[10];     int num[10];     int total=0;     int mydate[4];     int x1,x2,x3,x4,x5,x6;       for(i=0;i<10;i++)        num[i]=0;     for(i=0;i<10;i++)        guess[i]=i;       x1=comp(guess[0],guess[1],guess[2],guess[3]);     if(x1==0)     {        x6=comp(guess[0],guess[1],guess[2],guess[4]);        if(x6!=0)        {            num[4]=1;            total++;        }     }     else if(x1==4)     {        num[0]=1;        num[1]=1;        num[2]=1;        num[3]=1;        total+=4;        goto loop;     }     else     {        x2=comp(guess[4],guess[1],guess[2],guess[3]);        x3=comp(guess[0],guess[4],guess[2],guess[3]);        x4=comp(guess[0],guess[1],guess[4],guess[3]);        x5=comp(guess[0],guess[1],guess[2],guess[4]);        if(x2+x3+x4+x5>4*x1)         {            num[4]=1;            total+=1;            if(x1==x2)            {               num[0]=1;               total++;            }            if(x1==x3)            {               num[1]=1;               total++;            }            if(x1==x4)            {               num[2]=1;               total++;            }            if(x1==x5)            {               num[3]=1;               total++;            }        }        else        {            if(x1>x2)            {               num[0]=1;               total++;            }            if(x1>x3)            {               num[1]=1;               total++;            }            if(x1>x4)            {               num[2]=1;               total++;            }            if(x1>x5)            {               num[3]=1;               total++;            }        }     }       //0,1,2,3,4已经确定是否出现。       x1=comp(guess[5],guess[6],guess[7],guess[8]);     if(x1==0)     {        x6=comp(guess[5],guess[6],guess[7],guess[9]);        if(x6!=0)        {            num[9]=1;            total++;        }     }     else if(x1==4)     {        num[5]=1;        num[6]=1;        num[7]=1;        num[8]=1;        total+=4;        goto loop;     }     else     {        x2=comp(guess[9],guess[6],guess[7],guess[8]);        x3=comp(guess[5],guess[9],guess[7],guess[8]);        x4=comp(guess[5],guess[6],guess[9],guess[8]);        x5=comp(guess[5],guess[6],guess[7],guess[9]);        if(x2+x3+x4+x5>4*x1)        {            num[9]=1;            total+=1;            if(x1==x2)            {               num[5]=1;               total++;            }            if(x1==x3)            {               num[6]=1;               total++;            }            if(x1==x4)            {               num[7]=1;               total++;            }            if(x1==x5)            {               num[8]=1;               total++;            }        }        else        {            if(x1>x2)            {               num[5]=1;               total++;            }            if(x1>x3)            {               num[6]=1;               total++;            }            if(x1>x4)            {               num[7]=1;               total++;            }            if(x1>x5)            {               num[8]=1;               total++;            }        }     }     loop:     j=0;     for(i=0;i<10;i++)     if(num[i]==1)     {        mydate[j]=i;        j++;     }        i=0;        while(1)        {            x1=s[i]/1000-1;            x2=s[i]/100%10-1;            x3=s[i]/10%10-1;            x4=s[i]%10-1;            if(comp2(mydate[x1],mydate[x2],mydate[x3],mydate[x4])==1)            {               cout<<"I get it,it is:";               cout<<mydate[x1]<<" "<<mydate[x2]<<" "               <<mydate[x3]<<" "<<mydate[x4]<<endl;               return 0;            }            i+=1;        } }     PS: 改了下程序,明天上机测试下. 说明: 首先你自己随便想4个数字,要求是4个数字的范围0-9且各不相同，但有顺序。要你猜这4个数字。电脑会猜你想的数字,对电脑每次猜的数字你要给一个评价.评价规则为:如果电脑猜的数字中一个数字和你给的数字相同且位置相同就得一个A,如果猜对了数字但位置不对就得一个B.电脑会一直猜直到猜中你想的数字. 最坏的情况电脑可能要猜36次,所以整天要你输入评价,还蛮麻烦的.所以测试这个程序并不简单..     相关文章: 猜数字游戏(解释) http://blog.programfan.com/article.asp?id=16825   对置顶贴猜数字的一点解释. http://blog.programfan.com/article.asp?id=16842  

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