How far can you make a stack of cards overhang a table? If you have one card, you can create a maximum overhang of half a card length. (We're assuming that the cards must be perpendicular to the table.) With two cards you can make the top card overhang the bottom one by half a card length, and the bottom one overhang the table by a third of a card length, for a total maximum overhang of 1/2 + 1/3 = 5/6 card lengths. In general you can make n cards overhang by 1/2 + 1/3 + 1/4 + ... + 1/(n + 1) card lengths, where the top card overhangs the second by 1/2, the second overhangs tha third by 1/3, the third overhangs the fourth by 1/4, etc., and the bottom card overhangs the table by 1/(n + 1). This is illustrated in the figure below. The input consists of one or more test cases, followed by a line containing the number 0.00 that signals the end of the input. Each test case is a single line containing a positive floating-point number c whose value is at least 0.01 and at most 5.20; c will contain exactly three digits.For each test case, output the minimum number of cards necessary to achieve an overhang of at least c card lengths. Use the exact output format shown in the examples. Sample Input:1.00 3.71 0.04 5.19 0.00 Sample Output:3 card(s) 61 card(s) 1 card(s) 273 card(s) #include<iostream>using namespace std;int main(){ double i=1.0,s=0.0; int k; while(i!=0.00) {  s=0.0;  cin>>i;  if(i==0.00)break;  for(k=2;k<1000;k++)  {   s+=1.0/k;   if(s>i)break;  }  k--;  cout<<k<<" card(s)"<<endl; } return 0;}

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