#include <stdio.h>
int F(int n)
{ //n! = 2^k * k! * a  
 //k = n / 2, a不含因子2
 
	int sum = 0;
	while(n >= 2)
	{
		sum += n / 2; 
		n /= 2;
	}
	return sum;
}

int main(void)
{
	int n, k;
	while(EOF != scanf("%d%d", &n, &k))
	{	 
		if(F(n) > F(n - k) + F(k))
		   printf("0\n");
    	else
    	   printf("1\n");
	}
	return 0;
}

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