Problem description Suppose you are reading byte streams from any device, representing IP addresses. Your task is to convert a 32 characters long sequence of '1s' and '0s' (bits) to a dotted decimal format. A dotted decimal format for an IP address is form by grouping 8 bits at a time and converting the binary representation to decimal representation. Any 8 bits is a valid part of an IP address. To convert binary numbers to decimal numbers remember that both are positional numerical systems, where the first 8 positions of the binary systems are: 27 26 25 24 23 22 21 20 128 64 32 16 8 4 2 1  Input The input will have a number N (1<=N<=9) in its first line representing the number of streams to convert. N lines will follow.  Output The output must have N lines with a doted decimal IP address. A dotted decimal IP address is formed by grouping 8 bit at the time and converting the binary representation to decimal representation.  Sample Input 400000000000000000000000000000000 00000011100000001111111111111111 11001011100001001110010110000000 01010000000100000000000000000001  Sample Output 0.0.0.03.128.255.255203.132.229.12880.16.0.1 Problem Source MCA 2004  #include <stdio.h>  int main(){ int j,i,n,a[10][4],m;  char  str[40];   scanf("%d",&j);  for(i = 0; i < j; i ++) { scanf("%s",str);   for(n = 0,m = 0; m <= 7; m ++)  n = (str[m] - '0') + 2 * n;   a[i][0] = n;    for(n = 0,m = 8; m <= 15; m ++)  n = (str[m] - '0') + 2 * n;   a[i][1] = n;    for(n = 0,m = 16; m <= 23; m ++)  n = (str[m] - '0') + 2 * n;   a[i][2] = n;   for(n = 0,m = 24; m <= 31; m ++)  n = (str[m] - '0') + 2 * n;   a[i][3] = n;  }  for(i = 0; i < j; i ++) printf("%d.%d.%d.%d\n",a[i][0],a[i][1],a[i][2],a[i][3]);  return 0;}

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