博文
一元二次方程的解(2005-09-08 15:10:00)
摘要：#include <math.h>
main()
{
float a,b,c,disc,x1,x2,realpart,imgpart;
scanf("a=%f,b=%f,c=%f",&a,&b,&c);
disc=b*b-4*a*c;
if (fabs(a)<=1e-6) printf("please check a,a!=0\n");
else
{
if (fabs(disc)<=1e-6)
{
x1=x2=-b/(2*a);
printf("%8.4f,%8.4f\n",x1,x2);
}
else if (disc>1e-6)
{
x1=(-b+sqrt(disc))/(2*a);
x2=(-b-sqrt(disc))/(2*a);
printf("%8.4f,%8.4f\n",x1,x2);
}
else
{
realpart=-b/(2*a);
imgpart=sqrt(-disc)/(2*a);
printf("x1=%8.......
闰年程序(2005-09-08 11:08:00)
摘要：main()
{
int year,leap;
scanf("%d",&year);
if ((year%4==0&&year%100!=0)||(year%100==0&&year%400==0)) leap=1;
else leap=0;
switch(leap)
{
case 1:printf("a leap year");
case 0:printf("not a leap year");
}
}
......