问题： 打印1+11+111+1111+11111=           2+22+222+2222+22222=           ....................           9+99+999+9999+99999=#include int main(){  int i, j, n, sum=0;  for(i = 1;i <= 9;i++){    sum = 0;     for(j = 0,n = 0; j < 5; j++){      n *= 10;      n += i;      sum += n;      if(j == 4) printf("%d = ",n);      else printf("%d+",n);    }    printf("%d\n",sum);  }   getchar();  return 0;  }结果如下：1+11+111+1111+11111=123452+22+222+2222+22222=246903+33+333+3333+33333=370354+44+444+4444+44444=493805+55+555+5555+55555=617256+66+666+6666+66666=740707+77+777+7777+77777=864158+88+888+8888+88888=987609+99+999+9999+99999=111105

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